Django file upload
Some interesting examples on how to handle file uploads using Django: * Code snippet posted on Djangosnippets. The file is saved by declaring a save()
method in the form class. This method is invoked when calling form.save()
, which is standard Django newforms practice. (Note that this snipped uses clean_data
. As of Django version 0.96, clean_data
has been renamed to cleaned_data
, so you will have to change the code or it won't work) * Django image upload and validation. The author uses a model for the file and its related data. The uploaded file is saved by calling the save_FOO_file
method. (This method is automatically provided by Django for fields declared as models.ImageField
or models.FileField
in the model. See the db-api documentation.) Interesting, there seems to be no easy way of limiting the uploaded file size. The file can be rejected at validation time, but the data would have already been transfered.
A file upload recipe
After reading those posts, I think that a good recipe for handling file uploads in Django would be: * Write a django model for the uploaded file and its related data. Using a Django model makes sense, because it is usually necessary for the application to keep track of the uploaded files. * Write a subclass of form.Forms
and declare a clean_FOO
method for each models.FileInput
or models.ImageInput
fields declared in the model class. These clean_FOO methods are used to validate the uploaded files. * use a django view to receive the POST data, or display the form if no data is posted or errors are found. * save the file or files getting the data directly from the request.FILES
object, by writing a save()
method for the subclassed form or by calling save_FOO_file
for the model instance.
A simpler way to upload a file
The directory where the file is to be saved must be writable by the user that is running the Django server script. (The example uses MEDIA_ROOT as defined in settings.py
.)
from django import http
from django import newforms as forms
from django.shortcuts import render_to_response
from djangotest.settings import MEDIA_ROOT
class SimpleFileForm(forms.Form):
file = forms.Field(widget=forms.FileInput, required=False)
def directupload(request):
"""
Saves the file directly from the request object.
not be used on a real website. It does not validate
arbitrary script on the server.
"""
template = 'fileupload.html'
if request['method'] == 'POST':
if 'file' in request.FILES:
file = request.FILES['file']
# Other data on the request.FILES dictionary:
# filesize = len(file['content'])
# filetype = file['content-type']
filename = file['filename']
fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb')
fd.write(file['content'])
fd.close()
return http.HttpResponseRedirect(' upload_success.html')
else:
# display the form
form = SimpleFileForm()
return render_to_response(template, { 'form': form })
{% extends "base.html" %}
{% block body %}
<h1>Upload a file</h1>
<form action="." method="post" enctype="multipart/form-data">
{{ form }}
<type="submit" value="Upload" />
</form>
{% endblock %}